cos x= sqrt(3) - cos x. 0 < x < 2 pi?

anonymous

if somebody could please explain to me how in the world i would achieve the answer to this question it would be much appreciated. I'm an english and social guy, i can't math.

mike-g

cos x = sqrt(3)/2

x = pi/6 and 11pi/6

rocco

cos x= sqrt(3) - cos x

2cos x = sqrt(3)

cos x = sqrt(3) / 2

x = arccos(sqrt(3) / 2)

x = pi/6, 11pi/6