AP Calculus Derivative Problem (10 points!!)?

If h(x) = sin(f(x)), write an equation of the line tangent to h at the point where x = 1.

@ x =1, f(x)= 3pi/4, f'(x)=square root 2.

Can someone please help!!! 10 pts for best answer :)

Comments

  • To find the tangent line equation y=mx+c at x=1 on h(x):

    h(1)=sin(f(1)) = sin(3pi/4)=1/sqrt(2)

    h'(x)=cos(f(x)).f'(x) ... chain rule

    h'(1)=cos(f(1)).f'(1)

    =cos(3pi/4).sqrt(2) = -1

    m=h'(1)=-1

    find c in y=-x+c: subst

    c=1/sqrt(2) +1

    y=-x+1/sqrt(2) +1

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