(-1,8) and (-5,28) write an equation
assuming it is linear, slope is -5 so y-8=-5x-5 which equals y=-5x+3
P1 = (-1, 8) and P2 = (-5, 28)
m = (y1 - y2)/(x1 - x2) Slope equation
m = (8 - 28)/(-1 - (-5))
m = -20/(-1 + 5)
m = -20/4
m = -5 Slope
(Pick either given point.)
x = -1 and y = 8
(y - y1) = m(x - x1) Point-Slope Equation
y - 8 = -5(x - (-1))
y - 8 = -5(x + 1)
y - 8 = -5x - 5
y = -5x - 5 + 8
y = -5x + 3 Slope-Intercept Equation
5x + y = 3 Standard (or General) Equation
you find the gradient by 8-28 divided by -1--5 which equals -5 then sub into y=mx+c
so 8=-5(-1)+c
3=c
therefore y=-5x+3 assuming you mean a linear equation....
Comments
assuming it is linear, slope is -5 so y-8=-5x-5 which equals y=-5x+3
P1 = (-1, 8) and P2 = (-5, 28)
m = (y1 - y2)/(x1 - x2) Slope equation
m = (8 - 28)/(-1 - (-5))
m = -20/(-1 + 5)
m = -20/4
m = -5 Slope
(Pick either given point.)
x = -1 and y = 8
(y - y1) = m(x - x1) Point-Slope Equation
y - 8 = -5(x - (-1))
y - 8 = -5(x + 1)
y - 8 = -5x - 5
y = -5x - 5 + 8
y = -5x + 3 Slope-Intercept Equation
5x + y = 3 Standard (or General) Equation
you find the gradient by 8-28 divided by -1--5 which equals -5 then sub into y=mx+c
so 8=-5(-1)+c
3=c
therefore y=-5x+3 assuming you mean a linear equation....