How do i do this algebra 2 problem?

I need work please! The answer is (-4, -2) and (2,4) but idk how to do it.

Find the real solutions.

xy = 8

1/x-1/y=1/4

Comments

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  • xy=8 ; y = 8/x

    1/x - 1/(8/x) =1/4

    1/x - x/8 =1/4

    1 - (1/8)x^2 = x/4

    8 - x^2 = 2x

    x^2 + 2x - 8 = 0

    x^2 - 2x + 4x - 8 = 0

    x(x - 2) + 4(x - 2) = 0

    (x + 4)(x - 2) = 0

    x = -4, 2;

    y = 8/x

    when x = -4

    y = 8/-4

    y = -2

    (-4, -2)

    when x=2

    y = 8/2

    y = 4

    (2, 4)

    ~

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