Solve using determinants and cramers rule:
2x+3y-z=1
x+2y+2z=5
x-y+z=6
"T" s comments are true...but not the computations...bottom determinant = 14 , top = 42...thus x = 3
Check the Link for answer.
http://youtu.be/nNBZx_qtyZI
ICT Helps
http://www.icthelps.com/
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solving for x
top matrix(numerator)
...1...3...-1
...5...2...2
...6...-1...1
bottom matrix(denominator):
...2...3..-1
...1...2...2
...1...-1..1
determine
...1...3...-1..1..3
...5...2...2...5..2
...6...-1...1..6..-1
= (-12) + (-2) + (15) = 1
...2...3..-1..2..3
...1...2...2..1..2
...1...-1..1..1..-1
= (-2) + (4) + (3)
= 5
so x = 1/5
.... now solving for z and y you could use a 2x2 matrix, of course you could also just solve at that point with basic algebra
Comments
"T" s comments are true...but not the computations...bottom determinant = 14 , top = 42...thus x = 3
Check the Link for answer.
http://youtu.be/nNBZx_qtyZI
ICT Helps
http://www.icthelps.com/
http://www.youtube.com/user/icthelps
solving for x
top matrix(numerator)
...1...3...-1
...5...2...2
...6...-1...1
bottom matrix(denominator):
...2...3..-1
...1...2...2
...1...-1..1
determine
...1...3...-1..1..3
...5...2...2...5..2
...6...-1...1..6..-1
= (-12) + (-2) + (15) = 1
...2...3..-1..2..3
...1...2...2..1..2
...1...-1..1..1..-1
= (-2) + (4) + (3)
= 5
so x = 1/5
.... now solving for z and y you could use a 2x2 matrix, of course you could also just solve at that point with basic algebra