Math problem?

anonymous

Convert to rectangular coordinates

( 11, 3π/4 )

iggy-rocko

(x, y) =

(11cos(3pi/4), 11sin(3pi/4)) =

(11 * -√2/2, 11 * √2/2) =

(-11√2/2, 11√2/2)

lenpol7

Rec(11: (3pi/4) = (10.956... , 0.972...)

jos-j

{-(11/Sqrt[2]), 11/Sqrt[2]}

como

11 cos 3π/4 = - 11 / √2 = - 11 √2 / 2

11 sin 3π/4 = 11 / √2 = 11 √2 / 2

second quadrant

co-ordinates are (- 11 √2 / 2 , 11 √2 / 2)