An equilateral triangle with an area of ¾ √3 is inscribed within a circle. What's the area of the circle?
The answer is pi, but I don't understand how to do it. Please explain! Thanks
A=3√3/4
A=(1/2) sen 60 *L²
3√3/4=(1/2) √3/2 *L²
L²=3 ==>L=√3
cos 30º = (L/2)/r
√3/2=(√3/2)/r
r=1 ==>A=r²π=π
Comments
A=3√3/4
A=(1/2) sen 60 *L²
3√3/4=(1/2) √3/2 *L²
L²=3 ==>L=√3
cos 30º = (L/2)/r
√3/2=(√3/2)/r
r=1 ==>A=r²π=π