7th grade algebra help [:?
Find the slope of the line that contains (-8, -3) and (-8, -8).
How would you do this?
would you just do the same y2-y1 over x2-x1 formula?
if you could go step by step thatd be good, thanks!
Find the slope of the line that contains (-8, -3) and (-8, -8).
How would you do this?
would you just do the same y2-y1 over x2-x1 formula?
if you could go step by step thatd be good, thanks!
Comments
(y2-y1)/(x2-x1)=m m is the slope
(-8-(-3))/(-8-(-8))=m
5/0=m
and since it is impossible to divide by 0 the slope is undefined.
what you should do is use slope intercept form:y2-y1 over x2-x1...so it would be -8--3 over -8--8 which would equal -5 over 0
-8- -8/ -8- -3 = 0/-5 =0
slope is 0
thry and look at the vector between the 2 points (0 -5)
its a straight line down
The slope for that (line?) is undefined. (at least on a graph)
It goes straight up.
yes the formula is that only..
but if you do that way answer goes to infinity coz 0 comes in denominator.....
yeah use the formula you listed in your question...