A lift (an elevator, if you insist) of total laden mass 3654Kg is raised by 46m in 38s. If the winch motor is only 68% efficient, what is the power supplied to it in Watts? (g is 10ms-2)
power = energy/time
energy = work done = force x distance = 365.4J (3654/g) x 46 = 16808.4J
power = 16808.4/38 = 442.32W
68% = 442.32W
so, 100% = 650.48W (2DP)
hope that helps
Comments
power = energy/time
energy = work done = force x distance = 365.4J (3654/g) x 46 = 16808.4J
power = 16808.4/38 = 442.32W
68% = 442.32W
so, 100% = 650.48W (2DP)
hope that helps