Questões de matemática (FATORIAL)?
Pessoal, eu faltei aula por causa de uma viagem, e perdi a explicação
mas preciso entregar umas quetões, me ajudem?????
a) (n+3)! - (n+4)! / (n+2)!
b) (x+2)! / 3! x! = x! / (x-1)!
c) (n+2)! . (n-2)! / (n+1)! . (n-1)! = 4
Comments
a) (n+3)! - (n+4)! / (n+2)!
(n+3)(n+2)! - (n+4)(n+3)(n+2)! / (n+2)!
(n+3)- (n+4)(n+3)=
=n+3-{n²+3n+4n+12}
=n+3-n²-3n-4n-12
=-n²-6n-9
b) (x+2)! / 3! x! = x! / (x-1)!
(x+2)(x+1)x! / 3! x(x-1)! = x! / (x-1)!
(x+2)(x+1)/ 3! x = 1
(x+2)(x+1) = 3! x
x²+x+2x+2=6x
x²-3x-4=0
c) (n+2)! . (n-2)! / (n+1)! . (n-1)! = 4
(n+2)(n+1)! . (n-2)(n-1)! / (n+1)! . (n-1)! = 4
(n+2) (n-2)= 4
n²-4=4
n²-8=0
a) (n+3)! - n^2 - 7*n - 12
b)(1/6) * (x+2)! * x! = x
c) n + 2
----- = 4
n - 1
{n = 2}
a) (n+3)! - (n+4)! / (n+2)!
(n+3)(n+2)! - (n+4)(n+3)(n+2)! / (n+2)!
(n+3)- (n+4)(n+3)=
=n+3-{n²+3n+4n+12}
=n+3-n²-3n-4n-12
=-n²-6n-9
b) (x+2)! / 3! x! = x! / (x-1)!
(x+2)(x+1)x! / 3! x(x-1)! = x! / (x-1)!
(x+2)(x+1)/ 3! x = 1
(x+2)(x+1) = 3! x
x²+x+2x+2=6x
x²-3x-4=0
c) (n+2)! . (n-2)! / (n+1)! . (n-1)! = 4
(n+2)(n+1)! . (n-2)(n-1)! / (n+1)! . (n-1)! = 4
(n+2) (n-2)= 4
n²-4=4
n²-8=0