does | a | x a = a^2?

| a | = sqrt(a^2) so... a x | a | = a x sqrt(a^2) = sqrt(a^2 x a^2) = sqrt(a^4) = a^2

Can someone tell me if this is correct. plz i need to know, i will not give best answer to someone saying just 'yes'

Comments

  • Your 2nd step is wrong because k√p = sign(k)*√(k²p)

    So a*√(a²) = sign(a)*sqrt(a⁴)

  • Yes because when you add an exponent to a number your are saying how many times a number needs to be multiplied by itself. So a x a = a^2 the |'s around the first "a" mean absolute value which doesn't change anything in this equation.

    Hope this helps

  • how about giving best answer to someone who says no?

    let a = -1

    l -1 l * (-1) =? (-1)^2

    1 * (-1) =? 1

    -1 =? 1

    clearly -1 is not 1

  • | a | x a = -a^2 when a<0

    as IaI = -a

    IaI x a = a^2 when a>0

  • |a| = absolute value of a (assuming it's algebra) which also means a x a which means it equals a^2, so yes.

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