does | a | x a = a^2?
| a | = sqrt(a^2) so... a x | a | = a x sqrt(a^2) = sqrt(a^2 x a^2) = sqrt(a^4) = a^2
Can someone tell me if this is correct. plz i need to know, i will not give best answer to someone saying just 'yes'
| a | = sqrt(a^2) so... a x | a | = a x sqrt(a^2) = sqrt(a^2 x a^2) = sqrt(a^4) = a^2
Can someone tell me if this is correct. plz i need to know, i will not give best answer to someone saying just 'yes'
Comments
Your 2nd step is wrong because k√p = sign(k)*√(k²p)
So a*√(a²) = sign(a)*sqrt(a⁴)
Yes because when you add an exponent to a number your are saying how many times a number needs to be multiplied by itself. So a x a = a^2 the |'s around the first "a" mean absolute value which doesn't change anything in this equation.
Hope this helps
how about giving best answer to someone who says no?
let a = -1
l -1 l * (-1) =? (-1)^2
1 * (-1) =? 1
-1 =? 1
clearly -1 is not 1
| a | x a = -a^2 when a<0
as IaI = -a
IaI x a = a^2 when a>0
|a| = absolute value of a (assuming it's algebra) which also means a x a which means it equals a^2, so yes.