maximum monthly revenue?

On a certain route, an airline carries 7000 passengers per month, each paying $150. A market survey indicates that for each $1 decrease in the ticket price, the airline will gain 50 passengers.

**I've found:

the number of passengers per month, N, as a function of the ticket price, x:

N(x) = 7000+50(150-x)

= 15400-50x

monthly revenue for the route, R, as a function of the ticket price, x:

R(x) = (14500-50x)x

= 14500-50x^2

**How do I find the maximum monthly revenue?

Comments

  • N(x) = 7000 + 50*(150 - x)

    N(x) = 7000 + 7500 - 50*x

    N(x) = 14500 - 50*x

    R(x) = (14500 - 50*x)*x

    R(x) = 14500*x - 50*x^2

    **How do I find the maximum monthly revenue?

    diff(14500*x - 50*x^2, x) = 14500 - 100*x

    solve(14500 - 100*x = 0)

    x = 150$, ticket price

    R(x) = 14500*x - 50*x^2

    R(150) = 14500*150 - 50*150^2

    R(150) = $1,050,000, maximum monthly revenue!

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