y= x arccos x- √1-x^2
hola:
y= x arccos x- √(1-x^2) = x arccos x- (1-x^2)^(1/2)
y ' = arccos x - x/√(1 - x^2) - (1/2) (1-x^2)^( - 1/2) (- 2 x )
Saludos
Comments
hola:
y= x arccos x- √(1-x^2) = x arccos x- (1-x^2)^(1/2)
y ' = arccos x - x/√(1 - x^2) - (1/2) (1-x^2)^( - 1/2) (- 2 x )
Saludos