arccos(1/2)?
I'm pretty sure the answer is supposed to be pi/3, but I just wanted to confirm this. What is arccos(1/2) equal to in radians?
Update:What's really sad is that for my College Pre-Cal final exam I got this question with these answer choices:
A) -pi/6
pi/6
C) pi
D) No solution in the domain
E) 1
F) None of the above
When I chose F, None of the above, it was marked as incorrect. I guess I'm going to have to dispute this with the professor. Thanks guys.
Comments
cos θ = 1/2
θ = π / 3 , 5 π / 3 (quadrants 1 and 4)
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RE:
arccos(1/2)?
I'm pretty sure the answer is supposed to be pi/3, but I just wanted to confirm this. What is arccos(1/2) equal to in radians?
pi/3.
The correct answer is pi/3.
If you have copied the problem statement correctly, then F is the correct answer, and I suggest that you talk to your professor about it.
it is
π/3 ( 1st quadrent) or 5π/3 ( 4th quadrent)
[remember that cos is +ve in 1st & 4th quadrent, & -ve in 2nd & 3rd
sin is +ve in 1st & 2nd & -ve in 3rd & 4th ]
it can be pi/3 or -pi/3 as you said