Por favor me ajudemmmmm, 10 pontos
tgx = 4/5 , x ∈ I
We have :
1/cos²x = tg²x + 1
<=> 1/cos²x = (4/5)² + 1 = 41/25
<=> cos²x = 25/41
<=> cosx = 5√41 / 41
=> tgx = senx/cosx
<=> tgx . cosx = senx
<=> 4/5 . 5√41 / 41 = 4√41 / 41
=> secx = 1/cosx =√41 / 5
Comments
tgx = 4/5 , x ∈ I
We have :
1/cos²x = tg²x + 1
<=> 1/cos²x = (4/5)² + 1 = 41/25
<=> cos²x = 25/41
<=> cosx = 5√41 / 41
=> tgx = senx/cosx
<=> tgx . cosx = senx
<=> 4/5 . 5√41 / 41 = 4√41 / 41
=> secx = 1/cosx =√41 / 5