sendo tgx 4/5 0<x<pi/2 qual é o valor de secx senx e cosx?

Por favor me ajudemmmmm, 10 pontos

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  • tgx = 4/5 , x ∈ I

    We have :

    1/cos²x = tg²x + 1

    <=> 1/cos²x = (4/5)² + 1 = 41/25

    <=> cos²x = 25/41

    <=> cosx = 5√41 / 41

    => tgx = senx/cosx

    <=> tgx . cosx = senx

    <=> 4/5 . 5√41 / 41 = 4√41 / 41

    => secx = 1/cosx =√41 / 5

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