How do you do this chemistry problem?
A chemical reaction was used to produce 1.28 moles of copper(II) bicarbonate. What mass of copper(II) bicarbonate was produced?
A chemical reaction was used to produce 1.28 moles of copper(II) bicarbonate. What mass of copper(II) bicarbonate was produced?
Comments
Molar mass of copper(II) bicarbonate = 63.5 + 2*(1 + 12 + 3*16) g mol^-1
= 185.5 g mol^-1
Now, 1 mole of Cu(HCO3)2 = 185.5 g
Therefore, 1.28 moles = 237.44 g was produced