2 container problem Partial pressure of gas CHEM?

anonymous

Container a holds 752 mL of ideal gas at 2.60 atm. Container B holds 114 mL of ideal gas at 4.50 atm. If the gases are allowed to mix together, what is the resulting pressure

blackbeauty14

You need to use Dalton's law of partial pressures

First calculate the new volume: 752 + 114 = 866 ml

Now for each gas, calculate the new pressure using the above volume, and then add them up to get the new resulting pressure

Gas 1:

P1V1 = P2V2

2.6*752 = P2*866

or P2 = 2.6*752/866 = 2.26 atm

Gas 2:

P2 = 114*4.5/866 = 0.59 atm

P = P1 + P2 = 2.26 + 0.59 = 2.85 atm

There you have it