Algebra 1 problem!?!?!?

ken-phillips_60a32c625bcf0

A rental car company has two possible rate plans: $40 a day with unlimited mileage or $15 a day with a charge of $0.50 for each mile driven. How many miles would you need to drive on a three-day business trip to make the two rate plans cost the same?

Update:

Must be solved using algebra! Please use variables and show work.

abhinav

40x = 15x + .5y (x is the number of days and y is the number of miles)

You know x = 3.

40(3) = 15(3) + .5y

120 = 45 + .5y

.5y = 75

y = 150

Your answer is 150 miles.

pete-king_60a32c6453644

We know that 3 days will cost $120 using the first rate plan. So the goal is to take the second rate plan and make it equal to $120.

- we know that it will be $15 for each of the 3 days and that the total cost must be $120

15*3 + .5x = 120 where x = the total number of miles

.5x = 120 - 45

.5x = 75

x = 150

vicky-owen_60a32c65737e6

120-45=65/.5= 130 miles

anonymous

40 - 15 =25

25 divided by 0.5= 50 miles

There is your answer.