college algebra domain problem..?
given that f(x)=1/x and g(x)=9x+6, calculate f of g(x)=?
domain is all real numbers, accept?
g of f(x)= ?
domain all real numbers, accept?
f of f(x)=?
domain all real numbers, accept?
g of g(x)=?
domain is?
given that f(x)= 2/x-8 and g(x)=6/x+15 f+g=?
and the domain?
f-g=?
and the domain?
f(g)=?
and the domain?
f/g=?
and the domain?
Comments
f(x)=1/x and g(x)=9x+6
i) f of g(x)= f ( g(x) ) = 1/(9x+6)
Domain: All real numbers, and x cannot equal 0 or -6/9.
ii) g of f(x)= g( f(x) ) = 9/x+6
domain: All real numbers, x cannot equal 0 (-oo,0)U(0,+oo)
iii) f of f(x)= f ( f(x) ) = 1/(1/x) = x
Domain: All real numbers, x cannot equal 0. Why cant' x equal 0? Because we must redefine the domain to do so. Type 1/(1/x) in a calculator, and you will get a Error at x=0.
iv) g of g(x)= g( g(x) ) = 9(9x+6)+6 =....
domain: All real numbers (-oo,+oo)
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