Two jets left an airport at the same time. One traveled east at 300 mph. The other traveled South at 400 mph. How far apart were the jets at the end of an hour?
Show work.
Hint: let r be the separation between planes. Then by Pythagorean Theorem r^2=x^2+y^2
After 1 hour x = 300 and y=400
Use Pythagorous theorem for the distances of 300mi and 400 mi covered in 1 hr, are at rt angles
distance =sq root (300^2+400^2)=500mi ANS
mph stands for MILES PER HOUR so one traveled 300 miles and the other traveled 400 miles so they were 100 miles apart. i hope this helped.
yeah. pythagorean...-
300^2 x 400^2= distance^2
be sure to take the square root thingy :pp
Comments
Hint: let r be the separation between planes. Then by Pythagorean Theorem r^2=x^2+y^2
After 1 hour x = 300 and y=400
Use Pythagorous theorem for the distances of 300mi and 400 mi covered in 1 hr, are at rt angles
distance =sq root (300^2+400^2)=500mi ANS
mph stands for MILES PER HOUR so one traveled 300 miles and the other traveled 400 miles so they were 100 miles apart. i hope this helped.
yeah. pythagorean...-
300^2 x 400^2= distance^2
be sure to take the square root thingy :pp