Help, physics forces problem?

friction between the cup and the table is 0.39. Suddenly, the plane accelerates, its altitude remaining constant. What is the maximum acceleration that the plane can have without the cup sliding backward on the table?

Comments

  • The maximum frictional force = mu*N= mu*m*g. setting this equal to m*a and solving for a gives up the maximum acceleration before the cups moves backwards. So mu*m*g = m*a Therefore,

    a=mu*g = 0.39*9.80m/s^2 = 3.82m/s^2

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