Triangle LMN is congruent to triangle HIJ. Angle L measures 35 degrees, angle M measure 65 degrees, and angle I measures 2x + 10 degrees. Find the value of x.
Good enough, sketch a triangle, and mark the smallest perspective (x-forty) levels additionally mark the biggest angle x degrees. Now on the grounds that the smallest can be 20 degrees not up to the core attitude (the as-yet unmarked one) the core one must be (x-40)+20, as a result (x-20) degrees. Now, you must don't forget that the entire angles in a triangle need to add as much as 180 levels. So x + (x - forty) + (x - 20) = 180 take away brackets x + x - 40 + x - 20 = 180 simplify 3x - 60 = 180 add 60 to either side 3x = 240 divide either side by using three x = eighty Now you realize x, replacement it into the three x = eighty x - 40 = 40 x - 20 = 60
Comments
The way you have written it, Angle I = Angle M
so
2x + 10 = 65
2x = 55
x = 27.5
The angles of LMN are 65, 35 and 80 so 2x + 10 = 65, 35 or 80 depending on which are the corresponding vertices of the 2 triangles.
Good enough, sketch a triangle, and mark the smallest perspective (x-forty) levels additionally mark the biggest angle x degrees. Now on the grounds that the smallest can be 20 degrees not up to the core attitude (the as-yet unmarked one) the core one must be (x-40)+20, as a result (x-20) degrees. Now, you must don't forget that the entire angles in a triangle need to add as much as 180 levels. So x + (x - forty) + (x - 20) = 180 take away brackets x + x - 40 + x - 20 = 180 simplify 3x - 60 = 180 add 60 to either side 3x = 240 divide either side by using three x = eighty Now you realize x, replacement it into the three x = eighty x - 40 = 40 x - 20 = 60
angle L = angle H ------- 35°
angle M = angle I -------- 65° = 2x + 10
angle N = angle J
2x + 10 = 65
2x = 55
x = 27.5°
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