Algebra Word Problem...?
Can anyone figure this out?
. Translate to an algebra statement; do not solve:
Three times the difference of five and a twice a number yields the same result as the same number increased by four.
Can anyone figure this out?
. Translate to an algebra statement; do not solve:
Three times the difference of five and a twice a number yields the same result as the same number increased by four.
Comments
let number be x
then
3(5-2x)=x+4
hope it works
three times= 3*
difference of five and..., where ...=x, is 5-x, keep that to the side
twice an number= 2*y (where y is the number)
yields = "="
the number increased by four= y+4
put it all together now. remember that your x is the second part of the statement.
3(5-2x) = x+4 (I'm just replacing x with y, here)
The difference of five is: t - 5
three times the difference is: 3 * (t - 5)
z = 3 (t - 5)
Twice a number yields: 2z =
As the same number increased by four: t + 4
Therefore,
z = 3 (t - 5)
2z = t + 4
I think.
let x be the number. Then,
3(5 - 2x) = x + 4
3(2x-5) = x+4
3*(2x - 5) = x + 4
If the scholars cutting-edge grade is a ninety% then we’re of direction assuming it’s out of a hundred% ninety/a hundred Now because of the fact the scholars grade stronger 20% from the final grading era then you definately upload that to the previous a hundred% offering you with ninety/ a hundred and twenty = .75 and because grades are in probabilities you multiply .75 via a hundred offering you with 75% because of the fact the scholars previous grade
3(5-2x)=x+4
Btw.. x=11/7
3(5x-2x)=x+4
3(5x-2x)=x+4