find the probability using biomial distribution
n=64,x=3,p=.04
P(x|n) = nCx * p^(x) * (1-p)^(n-x)
where C is the combination operator.
P(x=3|n=64) = ( 64!/[(64-3)!3!]} * (0.04)^3 * (.96)^61
= 0.221 <= answer
I have no clue!!!
Comments
P(x|n) = nCx * p^(x) * (1-p)^(n-x)
where C is the combination operator.
P(x=3|n=64) = ( 64!/[(64-3)!3!]} * (0.04)^3 * (.96)^61
= 0.221 <= answer
I have no clue!!!