maths problem

C1.It is given that z=(p+2i)(i-3) .(complex no)

(a)If p is a real number, express z in standard form.

(b)If z is a purely imaginary number, find the value of p.

C2.If Alpha and Beta are the roots of the equation 2x^2+3=3x, find a quadratic equation in x with each of the following sets of roots.

(a)1/Alpha,1/Beta

(b) Alpha/Beta,Beta/Alpha

C3.(a)If the quadratic equation kx^2+(3k-1)x+(2k-1)=0 has two equal real roots and k is a constant, find the value of k.

(b)From the result of (a), solve the equation kx^2+(3k-1)x+(2k-1)=0 .

C4.Given that f(x)=x-3 and g(x)=1/x , where x is not 0 , find the values of the following.

(a)f(4)+g(1/4)(b)f(5)*g(1/2) (c) f(2)/g(2)

C5.In a factory, the total cost of producing n boxes of models is C(n) (in $), where .

(a)Find the total cost of producing 1 500 boxes of models.

(b)It is given that the selling price of each box of model is $120. Express the profit of selling n boxes of models as a function P(n) (in $).

(c)If 2 000 boxes of models are sold, find the profit of the factory.

Update:

where C(n)=25000+30n

Comments

  • C1.

    (a)

    z = (p + 2i)(i - 3)

    = pi - 3p - 2 - 6i

    = -(3p + 2) + (p - 6)i

    (b)

    Since z is a purely imaginary number, then its real part is 0.

    -(3p + 2) = 0

    p = -2/3

    C2.

    αand β are the roots of the equation2x²-3x + 3 = 0

    Sum of the roots: α + β = 3/2

    Product of the roots : αβ = 3/2

    (a)

    (1/α) + (1/β)

    = (α+ β)/αβ

    = (3/2)/(3/2)

    = 1

    (1/α)* (1/β)

    = 1/αβ

    = 1/(3/2)

    = 2/3

    The required equation is :

    x² - x + (2/3) = 0

    i.e. 3x²- 3x + 2 = 0

    (b)

    (α/β) + (β/α)

    = (α² + β²)/αβ

    = [(α+ β)²- 2αβ]/αβ

    = [(3/2)² - 2(3/2)]/(3/2)

    = -1/2

    (α/β)* (β/α)

    = 1

    The required equation is :

    x² +(1/2)x + 1 = 0

    i.e. 2x² + x + 2 = 0

    C3.

    (a)

    Since kx² + (3k - 1)x + (2k - 1) = 0 has two equal real roots, then Δ = 0

    (3k - 1)² -4k(2k - 1) = 0

    9k² - 6k+ 1 - 8k² + 4k= 0

    k² - 2k+ 1 = 0

    (k - 1)² = 0

    k = 1 (double roots)

    (b)

    Put k = 1 into the equation :

    (1)x² + [3(1) - 1)x + (2(1) - 1) = 0

    x² + 2x+ 1 = 0

    (x + 1)² = 0

    x = -1 (double roots)

    C4.

    (a)

    f(4) + g(1/4)

    = [(4) - 3) + [1/(1/4)]

    = 1 + 4

    = 5

    (b)

    f(5) * g(1/2)

    = [(5) - 3) * [1/(1/2)]

    = 2 * 2

    = 4

    (c)

    f(2) / g(2)

    = [(2) - 3] / (1/2)

    = -1 * 2

    = -2

    C5.

    The question is incomplete, something has been missed :

    "Ina factory, the total cost of producing n boxes of models is C(n) (in $), where ......??????"

    2012-07-06 23:40:47 補充:

    C5.

    (a)

    C(1500)

    = 25000 + 30(1500)

    = 70000

    Total cost = $70000 ...... (answer)

    (b)

    P(n) = 120n ...... (answer)

    (c)

    P(2000) - C(2000)

    = 120(2000) - [25000 + 30(2000)]

    = 155000

    Profit of the factory = $155000 ...... (answer)

Sign In or Register to comment.