Pergunta de matemática?

luciana

(16^(x-1) . 4 ^x)/32=4

elliot-chapman_60c292a38f6ca

(16^(x-1) . 4 ^x)/32=4

4^2(x-1) . 4^x = 4 x 32 = 128 = 2^7

2^4(x-1) . 2^2x = 2^7

2^(4x - 4 + 2x) = 2^7

4x - 4 + 2x = 7

6x = 11

x = 11/6

capivara56

16^(x - 1) = (4²)^(x - 1) = 4^2(x - 1) = 4^(2x - 2)

4^(2x - 2) * 4^x = 128

4^(3x - 2) = 128

Mas 128 = 2⁷

4^(3x - 2) = (2²)^(3x - 2) = 2^(6x - 4)

2^(6x - 4) = 2⁷

6x - 4 = 7

6x = 11

x = 11/6