(fei-sp) qual é o centro e o raio da circunferencia da equação x² + y² = 2(x-y)+1
x²+y²=2(x-y)+1
x²+y²-2x+2y-1=0
a=kx/-2=-2/-2=1 >>
b=ky/-2=2/-2=-1 >>
r²=a²+b² -f -> f=-1 <<~~
r²=1²+(-1)² - (-1)
r²=1+1+1
r²=3
r=√3 <<~~
C(1,-1) e r=√3
Comments
x²+y²=2(x-y)+1
x²+y²-2x+2y-1=0
a=kx/-2=-2/-2=1 >>
b=ky/-2=2/-2=-1 >>
r²=a²+b² -f -> f=-1 <<~~
r²=1²+(-1)² - (-1)
r²=1+1+1
r²=3
r=√3 <<~~
C(1,-1) e r=√3