how do I solve this natural logarithm problem?

shorty11

ex: e 0.006x =30

leo

take the ln of both sides

ln e^0.006x = ln 30

0.006x = 3.40

x= 566.866

como

e^(0.006x) = 30

Take logs of both sides

log(e^(0.006x) = log 30

0.006 x = log 30

x = log 30 / 0.006

x = 566.9

santmann2002

Take ln of both sides

0.006x =ln30 x= (ln30)/0.006 =566.87