how do I solve this natural logarithm problem?

Comments

  • leoleo

    take the ln of both sides

    ln e^0.006x = ln 30

    0.006x = 3.40

    x= 566.866

  • comocomo

    e^(0.006x) = 30

    Take logs of both sides

    log(e^(0.006x) = log 30

    0.006 x = log 30

    x = log 30 / 0.006

    x = 566.9

  • santmann2002santmann2002

    Take ln of both sides

    0.006x =ln30 x= (ln30)/0.006 =566.87

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