a. calculate the mass of MnO2 needed to produced 25.0 g of Cl2
and what mass of MnCl2 is produced when 0.091 g of Cl2 is generated?
moles of Cl2: 25 g/70.91 g/mole=0.35 moles
from bal. rxn., 1 mole of Cl2 is produced from 1 mole MnO2
0.35 moles x molec. wt. MnO2)g/mole)= ans.
from bal. rxn. 1 mole of Cl2 is produced with 1 mole of MnCl2 and 2 moles of H2O
moles Cl2: 0.091 g Cl2/70.91 g/mole Cl2=0.0013 moles Cl2
0.0013 moles x molec. wt. MnCl2(g/mole)= ans.
Comments
moles of Cl2: 25 g/70.91 g/mole=0.35 moles
from bal. rxn., 1 mole of Cl2 is produced from 1 mole MnO2
0.35 moles x molec. wt. MnO2)g/mole)= ans.
from bal. rxn. 1 mole of Cl2 is produced with 1 mole of MnCl2 and 2 moles of H2O
moles Cl2: 0.091 g Cl2/70.91 g/mole Cl2=0.0013 moles Cl2
0.0013 moles x molec. wt. MnCl2(g/mole)= ans.