algebra problem?

how is 2/3d+3b+d= solved

Update:

one more problem...

9x+2y-4y-6x

the 2y should be an exponant 2y to the 3rd power

Comments

  • turn all of the numbers into fractions.

    (2/3)d+(3)b+(3/3)d

    (2/3)+(3/3)=5/3

    so

    (5/3)d+(3)b

    with nothing on the other side of the equal sign it can't be solved further

    also since there are two variables you would need a second equation.

  • if you take the quotient of the multiple you will figure out the exponent is very closely equal the Explicit Formula of a Sequence. Then, you have to use the Compounded Continuously Compression of the square root of 23 using the Half-Closed Interval with the General Form for the Equation of a Line with the help of the Multiplicative Inverse of a Matrix and the Oblique Asymptote you can find the Rationalizing the Denominator which you use to find the Symmetric with Respect to the Origin which helps solve the problem!

  • It's 5/3d + 3b. Since there are 2 variables, you can't add those 2 together.

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