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Comments
Use:
[r₁(cos θ₁ + i sin θ₁)]/[r₂(cos θ₂ + i sinθ₂)] = r₁/r₂ * [cos(θ₁ - θ₂) + i sin (θ₁ - θ₂)].
You can easily derive this by using Euler's formula as:
[r₁(cos θ₁ + i sin θ₁)]/[r₂(cos θ₂ + i sinθ₂)]
=> [r₁e^(θ₁)]/[r₂e^(θ₂)]
= r₁/r₂ * e^(θ₁ - θ₂)
= r₁/r₂ * [cos(θ₁ - θ₂) + i sin(θ₁ - θ₂)].
So we have:
[15(cos 270° + i sin 270°)]/[3(cos 30° + i sin 30°)]
= 15/3 * [cos(270° - 30°) + i sin (270° - 30°)]
= 5(cos 240° + i sin 240°)
= 5(-1/2 - i√3/2)
= -5/2 - 5i√3/2.
I hope this helps!
cis 270 = e^i270
15/3 e^i(270-30) = 5e^i240
5 cis 240
5 cis 240° = 5 (cos 240° + i sin 240°) = 5(-1/2 + i (-√3/2)) = -5/2 - 5√3/2 i
15 /_ 270
----------------
3 /_ 30
5 /_ 240 °
5 ( cos 240 ° + i sin 240 ° )
5 ( -1/2 - i √3/2 )
(- 5/2) ( 1 + i √3 )
if you're undesirable at arithmetics, then you really doesn't do properly in computing gadget technological understanding. in case you opt for to get into computing gadget networking, you do not opt for a level for that. you'll opt for to get CISCO certification- CCNA. then you really can locate paintings as a community technician or associate. there is also certification provided via microsoft- Microsoft qualified suggestions professional (MCSE). this may prepare you to paintings as a device administrator for installation and troubleshooting all microsoft products. for a lot of those jobs, you do not opt for a level. Certification and experience concerns. perhaps after many years experience, you'll get a employer degree with it to get into mangement positions of networking container. sturdy success :-)