Alguém ajuda?
0,3 = 3/10
1,5 = 15/10
log15/10 na base 3/10 = x
log15/10 / log3/10 = x
______________________________________…
log15/10 = log15-log10
log15/10 = log(3.5) - 1
log15/10 = log3+log5 - 1
log15/10 = 0,48+0,70-1
log15/10 = 0,18
log3/10 = log3-log10
log3/10 = 0,48-1
log3/10 = -0,52
0,18/-0,52 = x
x = -0,34 <------------------------------
Oi Raquel, bom dia! Como vai?
Dados : log5=0,70 e log3=0,48
(0,3)^x = 1,5
log(0,3)^x = log 1,5
x log 0,3 = log 1,5
x(log 0,3) = log 1,5
x(log3/10) = log15/10
x( log3 - log 10) = (log 3 + log5)/log10 como log10 = 1
x(log3 -1) = log 3 + log 5
x.0,48 -x = 0,48 + 0,70
0,52 x = 1,18
x = 1,18/0,52 =~2,27
O que seriam logs?
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Comments
0,3 = 3/10
1,5 = 15/10
log15/10 na base 3/10 = x
log15/10 / log3/10 = x
______________________________________…
log15/10 = log15-log10
log15/10 = log(3.5) - 1
log15/10 = log3+log5 - 1
log15/10 = 0,48+0,70-1
log15/10 = 0,18
log3/10 = log3-log10
log3/10 = 0,48-1
log3/10 = -0,52
______________________________________…
log15/10 / log3/10 = x
0,18/-0,52 = x
x = -0,34 <------------------------------
Oi Raquel, bom dia! Como vai?
Dados : log5=0,70 e log3=0,48
(0,3)^x = 1,5
log(0,3)^x = log 1,5
x log 0,3 = log 1,5
x(log 0,3) = log 1,5
x(log3/10) = log15/10
x( log3 - log 10) = (log 3 + log5)/log10 como log10 = 1
x(log3 -1) = log 3 + log 5
x.0,48 -x = 0,48 + 0,70
0,52 x = 1,18
x = 1,18/0,52 =~2,27
O que seriam logs?
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