1over4(7+3g)= negative g over 8.
show all the steps and explain what you did.
thanks(:
First reciprocate on both sides you get, 4(7+3g) = - 8/g
Divide both sides by 4. Now you will get 7+3g = -2/g
Now multiply both by g there by you get 7g + 3g^2 = -2
Bring -2 to the left side. So 3g^2 + 7g + 2 = 0
Factorising, 3g^2 + 6g + g + 2 = 0
That is, 3g(g+2) + 1(g+2) = 0
Or, (g+2)(3g+1) = 0
Two options g+2 = 0 or 3g+1= 0.
So solution set for g is {-2, -1/3}
Comments
First reciprocate on both sides you get, 4(7+3g) = - 8/g
Divide both sides by 4. Now you will get 7+3g = -2/g
Now multiply both by g there by you get 7g + 3g^2 = -2
Bring -2 to the left side. So 3g^2 + 7g + 2 = 0
Factorising, 3g^2 + 6g + g + 2 = 0
That is, 3g(g+2) + 1(g+2) = 0
Or, (g+2)(3g+1) = 0
Two options g+2 = 0 or 3g+1= 0.
So solution set for g is {-2, -1/3}