How do you factor 12x^2 + 36 x?
I have some factoring problems 
can you show me how to factor
1. 12x^2 + 36x
2. Y^2- 7y + 12
3. 36y^2 - 16
4. 3x^2 + 13x +4
5. 6x^2- 13x +5
I have some factoring problems can you show me how to factor
1. 12x^2 + 36x
2. Y^2- 7y + 12
3. 36y^2 - 16
4. 3x^2 + 13x +4
5. 6x^2- 13x +5
Comments
1. (x)(12x+36)
(12)(x)(x+3)
(12x))(x+3)
2. y^2 -7y +12
(y-3)(y-4)
(To factor these types of problems, you can either use the quadratic formula or use this method: look at the middle term's coefficient, then the last term's coefficient (the -7 and the 12 here). Think of factors of 12 that add up to -7 (here it is -3 and -4).
3. 36y^2 -16
(6y+4)(6y-4)
(This is called a perfect square polynomial. If both terms are perfect squares, and the last term is negative with no middle term, you may use this method. The first and last terms are squared, and then the last term is put in positive and negative form.) For example:
x^2 -49 becomes (x-7)(x+7)
4. (3x+1)(x-4)
5. (3x+1)(2x-5)
1. 12x^2 + 36x = 12x(x+3)
2. Y^2- 7y + 12 = (y-4)(y-3)
3. 36y^2 - 16 = 4(9y^2 - 4)
= 4(3y+2)(3y-2)
4. 3x^2 + 13x +4 = (3x+1)(x+4)
5. 6x^2- 13x +5 = (3x-5)(2x-1)
1. 12x(x + 3)
2. (y-3)(y-4)
3. (12x+8)(3x-2)
4. (3x+1)(x+4)
5. (3x-5)(2x-1)
1.12x(x+3)
2.y^2-7y+12
=y^2-3y-4y+12
=y(y-3)-4(y-3)
=(y-3)(y-4)
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