vidhu-l
vidhu-l
About
- Username
- vidhu-l
- Joined
- Visits
- 0
- Last Active
- Roles
- Member
Comments
-
this is in the form ax^2+bx+c so use the formula -b+((b^2-4ac)^(1/2)/2a) and -b-((b^2-4ac)^(1/2)/2a)... substitute the values accordingly and u 'll get the two roots as 2 +((92)^(1/2))/6 and 2 -((92)^(1/2))/6
-
this is in the form ax^2+bx+c so use the formula -b+((b^2-4ac)^(1/2)/2a) and -b-((b^2-4ac)^(1/2)/2a)... substitute the values accordingly and u 'll get the two roots as 2 +((92)^(1/2))/6 and 2 -((92)^(1/2))/6
-
this is in the form ax^2+bx+c so use the formula -b+((b^2-4ac)^(1/2)/2a) and -b-((b^2-4ac)^(1/2)/2a)... substitute the values accordingly and u 'll get the two roots as 2 +((92)^(1/2))/6 and 2 -((92)^(1/2))/6
-
this is in the form ax^2+bx+c so use the formula -b+((b^2-4ac)^(1/2)/2a) and -b-((b^2-4ac)^(1/2)/2a)... substitute the values accordingly and u 'll get the two roots as 2 +((92)^(1/2))/6 and 2 -((92)^(1/2))/6