Comments

• secondo me e troppo presto...nn concederti subito..xk poi potresti anke pentirtene ...aspetta un altro po e cmq nn farlo cn lui sl xk nn lo vuoi perderlo o k altro..ma sl qnd t sentirai davvero pronta tu! buona fort..kiss

  in Ciao ragazzi ho veramente bisogno di voi..? Comment by sweetprincess June 2021
• secondo me e troppo presto...nn concederti subito..xk poi potresti anke pentirtene ...aspetta un altro po e cmq nn farlo cn lui sl xk nn lo vuoi perderlo o k altro..ma sl qnd t sentirai davvero pronta tu! buona fort..kiss

  in Ciao ragazzi ho veramente bisogno di voi..? Comment by sweetprincess June 2021
• 1) Well since the mass of each reactant is not specified then the only thing you have to do is look at the equation, you have 1mol of C3H8 and 5mol of O2, thus C3H8 is the limited reagant and O2 is in excess. 2) I am not sure about this one but i…

  in C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (l)? Comment by sweetprincess June 2021
• 1) Well since the mass of each reactant is not specified then the only thing you have to do is look at the equation, you have 1mol of C3H8 and 5mol of O2, thus C3H8 is the limited reagant and O2 is in excess. 2) I am not sure about this one but i…

  in C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (l)? Comment by sweetprincess May 2021
• 1) Well since the mass of each reactant is not specified then the only thing you have to do is look at the equation, you have 1mol of C3H8 and 5mol of O2, thus C3H8 is the limited reagant and O2 is in excess. 2) I am not sure about this one but i…

  in C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (l)? Comment by sweetprincess May 2021
• 1) Well since the mass of each reactant is not specified then the only thing you have to do is look at the equation, you have 1mol of C3H8 and 5mol of O2, thus C3H8 is the limited reagant and O2 is in excess. 2) I am not sure about this one but i…

  in C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (l)? Comment by sweetprincess May 2021
• 1) Well since the mass of each reactant is not specified then the only thing you have to do is look at the equation, you have 1mol of C3H8 and 5mol of O2, thus C3H8 is the limited reagant and O2 is in excess. 2) I am not sure about this one but i…

  in C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (l)? Comment by sweetprincess May 2021
• 1) Well since the mass of each reactant is not specified then the only thing you have to do is look at the equation, you have 1mol of C3H8 and 5mol of O2, thus C3H8 is the limited reagant and O2 is in excess. 2) I am not sure about this one but i…

  in C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (l)? Comment by sweetprincess May 2021
• 1) Well since the mass of each reactant is not specified then the only thing you have to do is look at the equation, you have 1mol of C3H8 and 5mol of O2, thus C3H8 is the limited reagant and O2 is in excess. 2) I am not sure about this one but i…

  in C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (l)? Comment by sweetprincess May 2021
• 1) Well since the mass of each reactant is not specified then the only thing you have to do is look at the equation, you have 1mol of C3H8 and 5mol of O2, thus C3H8 is the limited reagant and O2 is in excess. 2) I am not sure about this one but i…

  in C3H8 (g) + 5 O2 (g) ---> 3 CO2 (g) + 4 H2O (l)? Comment by sweetprincess May 2021