sophie-phillips_60a01b0e5e854
sophie-phillips_60a01b0e5e854
About
- Username
- sophie-phillips_60a01b0e5e854
- Joined
- Visits
- 0
- Last Active
- Roles
- Member
Comments
-
First we can divide a little bit: ...x²:(x-1) = x+1+(1/(x-1)) -(x²-x) -------- .......x .....-(x-1) ------------ ...........1 .........-1 ------------ ...........0 Now 0.5................0.5 ..∫x²:(x-1)dx = ∫x+1+(1/(x-1))]dx -1...…