ross-parker_6095be1082f07
ross-parker_6095be1082f07
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hipotenusa a, sombra b e c=10 Em qq triangulo retangulo qq cateto vale o produto da hipotenusa pelo seno do angulo oposto 10 = a*0,6 a= 10/0,6 = 100/6 a²=b²+c² b²=a²-c² b²= (100/6)²-10² b²= 10 000/36-100 ..mmc 36 36b²= 10 000-3600 =6 400…