#eleven: Multiply the two the numerator and the denominator by potential of the conjugate of the denominator. which potential multiply by potential of the sq. root of 5 minus the squareroot of x. #23: cube the two sides of the equation, which leaves you with: 3x-2=8. clean up from there. #31a: i do no longer remember the thank you to try this. #40: Divide 40 3 by potential of four, and get a the remainder of three. So the anser is comparable to it could be if i is raised to the third ability. If I remember wisely, i^3 is -i. #40 8: i do no longer understand. #40 9: that's (7x6x5x4x3x2x1)/(4x3x2x1). So in certainty that's 7x6x5. #fifty 4: the variety is all actual numbers (so that's for all organic log purposes that are like ln(x-c) whjere c is a few consistent). For the area, you could no longer enable the interior a organic log funtion ever be 0 or under 0. subsequently x is larger than 3 is the area. to locate the x-intercept: ln(x-3) =0. e^(ln(x-3))=e^0. x-3=a million. x=4 is the x-intercept.
Comments
Use the quadratic formula:
x = ( -b ± √(b^2 - 4ac) ) / 2a
x = ( -4 ± √(16 + 56) ) / 2
x = ( -4 ± √(72) ) / 2
x = ( -4 ± 6√(2) ) / 2
x = -2 ± 3√(2)
And your two answers are:
x = -2 + 3√(2)
x = -2 - 3√(2)
Which means:
p = -2
q = ±3
x² +4x – 14 = 0
x² +4x = 14
x² +4x + 4 = 14 + 4
(x + 2)² = 18
(x + 2) = ± √18
(x + 2) = ± 3√2
x = –2 ± 3√2
p=-2, q=3
x² + 4x - 14 = 0
x² + 2x = 14 + 2²
x² + 2x = 14 + 4
(x + 2)² = 18
x + 2 = ± √18
Answer: (x + 2 + √18)(x + 2 - √18) are the factors.
#eleven: Multiply the two the numerator and the denominator by potential of the conjugate of the denominator. which potential multiply by potential of the sq. root of 5 minus the squareroot of x. #23: cube the two sides of the equation, which leaves you with: 3x-2=8. clean up from there. #31a: i do no longer remember the thank you to try this. #40: Divide 40 3 by potential of four, and get a the remainder of three. So the anser is comparable to it could be if i is raised to the third ability. If I remember wisely, i^3 is -i. #40 8: i do no longer understand. #40 9: that's (7x6x5x4x3x2x1)/(4x3x2x1). So in certainty that's 7x6x5. #fifty 4: the variety is all actual numbers (so that's for all organic log purposes that are like ln(x-c) whjere c is a few consistent). For the area, you could no longer enable the interior a organic log funtion ever be 0 or under 0. subsequently x is larger than 3 is the area. to locate the x-intercept: ln(x-3) =0. e^(ln(x-3))=e^0. x-3=a million. x=4 is the x-intercept.
Recall the quadratic formula for a x^2 + b x + c = 0;
x = [-b +/- sqrt( b^2 - 4 a c)] / (2 a)
Here, a = 1, b = 4, and c = -14, so
x = [-4 +/- sqrt( 16 - 4(1)(-14) )] / 2(1)
= [-4 +/- sqrt(72)] / 2
= [-4 +/- sqrt(2*36)] / 2
= [-4 +/- sqrt(2)*sqrt(36)] / 2
= [-4 +/- 6*sqrt(2)] / 2
= -2 +/- 3*sqrt(2)
So, p = -2 and q = 3.
I hope that helped.