Math Problem. 8th grade level help?

Comments

• faith-h

  May 2021

  How I was taught was this...

  2x+3y=6 *First subtract the 6 by 2x to eliminate 2x.

  3y=6-2x *Then divide 6 by 3 to eliminate the 3.

  y=2-2x *Your answer should be Y=2-2x.
• d-m

  May 2021

  2x + 3y = 6 (2,1)

  first solve for the slope...the slope is the number in front of x when y is isolated

  2x + 3y = 6 move the 2x over (remember to change the sign)

  3y = -2x + 6 divide everything by 3 to isolate y

  y= -2/3x + 2 the slope of this equation is -2/3

  now write your equation using the given point and a slope of -2/3

  1 = -2/3(2) + 2 this is what I got

  sorry, I forgot to put it into standard form

  2/3(2) + 1 = 2
• anonymous

  May 2021

  2x+3y=6

  3y=-2x+6

  y= -2/3x +2 m= -2/3

  well now you have the points and the slope and you can get going.

  y = - 2/3x +b now we got to plug in the points to find b, the y-intercept

  1= -2/3(2)+b

  1= -4/3 +b

  b= 7/3

  [y= -2/3 x + 7/3] (3)

  2x+ 3y= 7

  so the equation parallel to 2x+3y=6 is 2x+ 3y= 7
• reece-ross_609c45ab94146

  May 2021

  you're leaving a lot out here but I think I may have the answer. assuming the (4,6) point is an endpoint of a line and that endpoint also is a point on the circle, then you should be able to find the other end of the line where it intersects the circle. Notice that you can go over 2 to the right and up 3 to get to the given intersection (draw this out). if you go 2 left and down 3 from the circle's center, you should be able to find the other endpoint of the line. This would be (0,0) the origin.
• math-h

  May 2021

  y = mx + c

  The slope is 2 so,

  y = 2x + c

  If it passes through (2, 1):

  1 = 2(2) + c

  c = 1 -4 = -3

  So the equation would be

  y = 2x -3

  In standard form:

  2x - y = 3
• alwaysconfused

  May 2021

  theres a formula and i believe it is (y-y1)=m(x-x1) so i'd be y-1=2(x-2) and slove from there