4 C3H5(NO3)3(s) 12 CO2(g) + 10 H2O(g) + 6 N2(g) + O2(g)?
Calculate the total volume of gases when collected at 1.2 atm and 25°C from 2.9 multiplied by 102 g of nitroglycerin.
im not understanding how to get the number of moles for each ..
Calculate the total volume of gases when collected at 1.2 atm and 25°C from 2.9 multiplied by 102 g of nitroglycerin.
im not understanding how to get the number of moles for each ..
Comments
am i interpreting this 2.9 multiplied by 102 g
corrctly as 290. grams
that's a lot of nitro
find moles of nitro, using molar mass:
2.9 e2 grams @ 227.09 g/mol =
1.277 moles of nitro glycerin
by the equation
4 C3H5(NO3)3(s) --> 12 CO2(g) + 10 H2O(g) + 6 N2(g) + O2(g)
4 moles of nitro produces 29 moles of gases
so
1.277 moles of nitro glycerin @ 29 mol gases / 4 mol nitro = 9.258 moles of gases
PV = nRT
(1.2 atm)(Litres) = (9.258 moles)(0.08206 L-atm/mol-K)(298K)
Litres = 188.67 litres of gases
in your 2 sig fig problem,
your answer should be rounded off to
190 Litres of gases