A boy of mass 30kg jumps with a velocity of 2.0 m/s into a stationary wagon of mass 40 kg. What is the final velocity?
Use conservation of momentum to solve this problem.
m1 * u1 + m2 * u2 = (m1+m2) * V
m1 = 30 kg = mass of the boy
u1 = 2.0 m/s = velocity of the boy before
m2 = 40 Kg = mass of the wagon
u 2 = 0 m/s = velocity of wagon before.
V = 30*2 / (30 + 40)
V = 0.86 m/s <=== This's the final velocity.
Comments
Use conservation of momentum to solve this problem.
m1 * u1 + m2 * u2 = (m1+m2) * V
m1 = 30 kg = mass of the boy
u1 = 2.0 m/s = velocity of the boy before
m2 = 40 Kg = mass of the wagon
u 2 = 0 m/s = velocity of wagon before.
V = 30*2 / (30 + 40)
V = 0.86 m/s <=== This's the final velocity.