2C2H6+7O2-->4CO2+6H2O?

a) how many moles of O2 are needed for the complete combustion of 15.0 mol of ethane?

b) how many grams of CO2 are produced for each 8.00g of H2O produced?

need help getting answers dont understand :'(

Comments

  • a) 15 mol C2H6 X 7 mol O2/

    2 mol C2H6 = 52.5 mol O2

    b) 8.00g H2O X 1 mol H2O X 4 mol CO2 X 44.0098 g CO2/

    18.0182 g H2O X 6 mol H2O X 1 mol CO2 = 1408.3136/108.1092 = 13.0 g CO2

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