QUESTION 2:
What are the 16 standard angles for Trigonometry?
[I need to know because I'm trying to memorize all the fundamentals for Calculus], please help.
a^3+-b^3= (a+-b)(a^2-+ab+b^2)
16 angles would be 0,30,45,60,90 and add 90 to each of these until you get 270,300,315,330,360
sum of cubes and difference of cubes
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
The thing to remember is the SOAP method
Same
Opposite
Always Positive
This gives the signs to use
a^3 + b^3 = (a +(same) b)(a^2 -(opposite) ab +(always positive) b^2)
a^3 - b^3 = (a -(same) b)(a^2 +(opposite) ab +(always positive) b^2)
a^3+b^3 = (a+b)(a^2-ab+b^2)
a^3-b^3 = (a-b)(a^2+ab+b^2)
Sum/difference of cubes:
a³ ± b³ = (a ± b)(a² â ab + b²)
For the second look at any, literally any, "unit circle." <- Google that
Comments
a^3+-b^3= (a+-b)(a^2-+ab+b^2)
16 angles would be 0,30,45,60,90 and add 90 to each of these until you get 270,300,315,330,360
sum of cubes and difference of cubes
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
The thing to remember is the SOAP method
Same
Opposite
Always Positive
This gives the signs to use
a^3 + b^3 = (a +(same) b)(a^2 -(opposite) ab +(always positive) b^2)
a^3 - b^3 = (a -(same) b)(a^2 +(opposite) ab +(always positive) b^2)
a^3+b^3 = (a+b)(a^2-ab+b^2)
a^3-b^3 = (a-b)(a^2+ab+b^2)
Sum/difference of cubes:
a³ ± b³ = (a ± b)(a² â ab + b²)
For the second look at any, literally any, "unit circle." <- Google that