C3H8 (g) + 5O2 (g) -> 3CO2 (g) + 4H2O (l)?

a. In the combustion of propane, how many moles of C3H8 are needed to combine completely with 2.96 mol O2?

b. How many moles of CO2 form?

c. How many moles of H2O form?

Comments

  • 1) The given reaction:

    C3H8 (g) + 5O2 (g) -> 3CO2 (g) + 4H2O (l)

    tells us that you need 1 mol of propane and 5 moles of O2 to form 3 moles of CO2 and 4 moles of water.

    Hence, ratio of propane / oxygen is:

    1 C3H8 / 5 O2 = 1/5

    #moles of C3H8 = (1/5)(2.96 moles O2) = 0.592 moles of O2

    2) 1 mol of C3H8 forms 3 moles of CO2 then,

    .....0.592 moles C3H8 forms x

    x = (0.592)(3) = 1.776 moles CO2

    3) 1 mol of C3H8 forms 4 moles of water then,

    .....0.592 moles C3H8 forms x

    x = (0.592)(4) = 2.368 moles H2O

    Hope it helps!

    Good luck!

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