What is the name and formula of the salt produced in the neutralization of sulfuric acid by potassium hydroxide? Write a balanced equation for the reaction - thank you!
H2SO4 + 2KOH ----> 2H2O + K2SO4
They both ionize/nuetralize to make water and potassium sulfate.
OK...Can you write the formula for sulfuric acid and potassium hydroxide?
When you neutralize any acid with any base, you form water and a salt. The salt in this case will contain potassium ions and sulfate ions.
Since the K+ ion has a charge of +1 and a sulfate ion SO42- has a charge of -2, you need to K+ for each SO42-.
So the equation will be:
H2SO4 + 2 KOH --> 2 H2O + K2SO4
The reaction is: KOH + H2SO4 = K2SO4 + H2O
This is not balanced and, as the products contain K x 2 we need more K at least.
2KOH + H2SO4 = K2SO4 + 2H2O...It is now balanced.
The name of the salt is Potassium Sulphate.
H2SO4 + 2KOH ------> K2SO4 + 2H2O
Sulfuric acid and potassium hydroxide form potassium sulfate and water.
Comments
H2SO4 + 2KOH ----> 2H2O + K2SO4
They both ionize/nuetralize to make water and potassium sulfate.
OK...Can you write the formula for sulfuric acid and potassium hydroxide?
When you neutralize any acid with any base, you form water and a salt. The salt in this case will contain potassium ions and sulfate ions.
Since the K+ ion has a charge of +1 and a sulfate ion SO42- has a charge of -2, you need to K+ for each SO42-.
So the equation will be:
H2SO4 + 2 KOH --> 2 H2O + K2SO4
The reaction is: KOH + H2SO4 = K2SO4 + H2O
This is not balanced and, as the products contain K x 2 we need more K at least.
2KOH + H2SO4 = K2SO4 + 2H2O...It is now balanced.
The name of the salt is Potassium Sulphate.
H2SO4 + 2KOH ------> K2SO4 + 2H2O
Sulfuric acid and potassium hydroxide form potassium sulfate and water.