Math problems - Algebra 2?

I need to figure out how to simplify -√1/121, √50/9, -2√10*√8, √288 ÷ √8, √85*√5, 2√126÷√14, -√189. Please help!

Comments

  • a) -1/11

    b) ???

    c) -2 root 80

    d) 6

    e) 5 root 17

    f) 6

    g) -3 root 21

  • 1. -√(1/121)

    121 = 11², so this is -√(1/11²) = -√(1/11)² = -1/11.

    2. √50/9

    50 = 25*2 = 5²*2, and 9 = 3², so this is √((5²*2)/(3²)) = (5/3)√2.

    (This assumes that the positive root is the default. In full, it's ±(5/3)√2.)

    3. -2√10*√8

    √10*√8 = √80. 80 = 16*5 = 4²*5, so this is -2√(4²*5) = -2*4√5 = -8√5.

    4. √288 ÷ √8

    288÷8 = 36, so √288 ÷ √8 = √(288/8) = √36 = 6.

    (This assumes that the positive root is the default. In full, it's ±6.)

    5. √85*√5

    85 = 17*5, so this is √(85*5) = √(17*5*5) = √(17*5²) = 5√17.

    (This assumes that the positive root is the default. In full, it's ±5√17.)

    6. 2√126÷√14,

    126÷14 = 9, so this is 2√(126÷14) = 2√9 = 2*3 = 6.

    (This assumes that the positive root is the default. In full, it's ±6.)

    7. -√189.

    189 = 11², so this is -√(11²) = -11.

  • sqrt(1/121) = sqrt(1^2 / 11^2) = sqrt(1/11)^2 = 1/11

    sqrt(50/9) = sqrt(2 * 5^2/3^2) = sqrt(2 * (5/3)^2) = sqrt(2) * 5/3

    -2*sqrt(10) * sqrt(8) = -2 * sqrt(80) = -2 * sqrt(16 * 5) = -8 * sqrt(5)

    All of the others use similar techniques.

  • I got here up with an answer of 7x^2-3/(x-3)(x+3)(x+2) and my TI 89 consents with my answer. First locate the liquid crystal reveal that's (x-3)(x+3)(x+2) x^2-9 is a distinction of two squares that are (x-3)(x+3) so now you've 4x/(x-3)(x+3) because the first portion of the priority.The denominator of the second one portion of the priority is a polynomial which will be factored into (x+3)(x+2). So now with the second one portion of the priority you've 3x+a million(x+3)(x+2) you presently prefer to position your liquid crystal reveal below the 4x and multiply it by the (x+2) that's lacking. next take the 3x+a million and position the liquid crystal reveal below it and multiply the numerator by the lacking portion of the liquid crystal reveal that's (x-3). Now your situation ought to look as if 4x(x+2) + (3x+a million)(x-3) all divided by the liquid crystal reveal of (x-3)(x+3)(x+2). next use the distributive sources for the first numerator and FOIL the second one numerator and receive (4x^2 + 8x) + (3x^2 -9x + x -3) all divided by the liquid crystal reveal of (x-3)(x+3)(x+2). next distribute the middle + time period and get 4x^2 + 8x + 3x^2 - 9x + x - 3. combine like words and get 4x^2 + 8x + 3x^2 - 8x -3. The 8x's cancel out and the x^2's combine to grant you 7x^2 - 3 all divided by the liquid crystal reveal of (x-3)(x+3)(x+2)

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