algebra 2 probabilty help?
how many four digit codes are possible if no digit may be used more than once ?
the answer is supposed to be 5040 but i just cant get it
Update:why do you stop at 7? 10*9*8*7?
how many four digit codes are possible if no digit may be used more than once ?
the answer is supposed to be 5040 but i just cant get it
Update:why do you stop at 7? 10*9*8*7?
Comments
10 digits
10*9*8*7 (aka 10P4
= 5040