algebra word problem, 10 p0ints!?

finley-thompson_60c03571e8179finley-thompson_60c03571e8179
in Science & Mathematics

The OFY student council voted to go to a baseball game for their annual trip. They bought 30 tickets. Some of the tickets cost $21 each, and some cost $27 each. The total cost of all the tickets was $696. How many of the $21 tickets did they buy?

Comments

  • molly-turner_60c035733bb92molly-turner_60c035733bb92

    a , b are the numbers of $21 and $27 tickets.

    a + b = 30

    21a + 27b = 696

    - 27a - 27b = -810

    21a + 27b = 696

    -6a = -114

    a = 19

  • ranjankarranjankar

    Let the no of 27$ tickets bought be x

    Then the no of 21$ tickets bought will be 30 -x

    Cost = 27x + 21 ( 30-x) = 696

    27x + 630 -21x = 696

    6x = 66

    x =11

    ANSWER 11 ( 27$) and 19 ( 21$)

  • notthejakenotthejake

    suppose they bought all 30 $21 tickets -- that would be $630.

    but they spent an additional $66

    each $27 ticket costs $6 more , so this is 11 $27 tickets

    (trade 11 $21 tickets for 11 $27 tickets adds an additional $66, making the total 630 + 66 = 696

    19 $21 tickets @ $399

    11 $27 tickets @ $297

    total: 30 tickets @ $696

  • sean-walsh_60c035752a14fsean-walsh_60c035752a14f

    Nineteen.

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