agebra math word problem?

the population on Earth is around 7,000,000,000. if the population grows at the rate 1% per year, how many people will be on the earth in 2020? explain why that is a problem

Comments

  • What does it matter? We are all dead by 2012 according to the Mayan Calender.

  • It is a compound growth question. Assuming the time period starts on Jan 1, 2010, that means that you have 10 years of compound growth.

    The long solution is:

    At year 0 (the present) you have 7,000,000,000 people.

    At year 1 you have 7,000,000,000 * 0.01 = 7,070,000,000 people

    At year 2 you have 7,070,000,000 * 0.01 = 7,140,700,000 people, and so on.

    and so on.

    The formala to solve for compound interest is

    Amount = Principal * (1+ Interest Rate / # of compound periods per year) to the power of (# of compound periods per year * the number of years)

    In this case, Amount = 7,000,000,000 * (1 + .01/1) ^(1*10)

    or 7,732,354,878

    As for what the problem with that is, is quite subjective, but there are concerns about adequate food, water, shelter, work, etc. for the population. Without them, there will be civil unrest. There are many who say that wars of the future won't be fought over oil or other natural resource which have been historically fought over, it will be over water and fertile land to grow food.

  • If something is 40% smaller, you purely subtract 40%. So 40% of 40 energy is sixteen: you are attempting this via multiplying 40 via 0.4. the respond could be 40 - sixteen = 24 A shorter way could purely be to multiply via 40 via 0.6, because of fact it incredibly is a million-0.4.

  • use the Time Value of Money (growth) function Future Amt = 7B*(1 + .01)^10 as in 10 years.

    Problem: lack of everything (food, water, land, jobs, oil,,,,, ) and the stress may cause wars.

  • Total population, assuming no one dies, would then be 7,732,355. You explain why it would be a problem, since I think it already is a problem

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